# JEE Advanced Circles and Family of Circles

Mathematics JEE Advanced level Practice Sample Model Question Paper, integral, Quadratic Equation, Logarithms, Fundamentals of Mathematics, Sets. Relations and Functions, Trigonometric (Ratios. Equation. General Solutions & Identities,

# Mathematics : Circle and Family of Circles Practice Question Paper of Circle on JEE Advanced Pattern (2018-2019)

## CIRCLE (Topic and Subtopic)

(1) Equation of circles in different forms, (2) Tangent to the circle, (3) Normal to the circle, (4) Length of intercepts and length of the tangent, (5) Position of point with respect to circle, (6) Equations of chords of a circles, (7) Director circle of circles, (8) Pole and polar of a circle, (9) Non-intersecting, intersecting, touching circles, (10) Coaxial system of circles, (11) Radical axis, (12) Orthogonal system

## Check our Question LEVEL for Main / Advanced Pattern

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Circle formulas

All points on the circumference of a circle

are equidistant from its center.

Diameter: d

Circumference: C

Area: K

d = 2r

C = 2 Pi r = Pi d

K = Pi r2 = Pi d2/4

C = 2 sqrt(Pi K)

K = C2/4 Pi = Cr/2

### Arc of a Circles

A curved portion of a circle.

Length: s

Central angle:

alpha (in degrees)

s = r theta = r alpha Pi/180

### Segment of a Circles

Either of the two regions into which a secant or a chord cuts a circle. (However, the formulas below assume that the segment is no larger than a semi-circle.)

Chord length: c

Height: h

Distance from center of circle to chord’s midpoint: d

Central angle: theta (in radians), alpha (in degrees)
Area: K

Arc length: s

theta = 2 arccos(d/r) = 2 arctan(c/(2d)) = 2 .

arcsin(c/(2r))

h = r – d
c = 2 sqrt(r2-d2) = 2r sin(theta/2) = 2d tan(theta/2)

= 2 sqrt[h(2r-h)]

d = sqrt(4r2-c2)/2 = r cos(theta/2) = c cot(theta/2)/2
K = r2[theta-sin(theta)]/2 = r2arccos([r-h]/r) – (r-h)sqrt(2rh-h2) = r2arccos(d/r) – d sqrt(r2-d2)
theta = s/r
K = r2[s/r – sin(s/r)]/2

###### Sector of a Circle

The pie-shaped piece of a circle ‘cut out’ by two radii.Central angle:

alpha (in degrees)

Area: K

Arc length: s
K = r2theta/2 = r2alpha Pi/360

theta = s/r

K = rs/2

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IIT-JEE Advanced syllabus has largely remained unchanged for the last 16 years! It is the same as the syllabus for IIT IIT-JEE in the previous years. This is the reason, we bring you 16 years of IIT IIT-JEE and IIT-JEE Advanced past year question Papers, as they cover same topics as specified in the IIT. IIT-JEE syllabus 2016. Ezyexams experts suggest that IIT-JEE Adv. 2016 Syllabus for Chem, Phy, Maths should have been the starting point of your IIT-JEE preparation. Even if you have not paid enough attention to it until now, pick up the IIT syllabus, now and check whether you have covered all the topics well or not.

### JEE Advanced 2016 Complete Syllabus

There are only minor changes between the IIT-JEE Mains syllabus 2016 and the IIT-JEEadv. syllabus. While the former is more tuned to the CBSE syllabi of Class XIth and Class XIIth, the latter includes topics from a wider range of boards.

#### Attention !

Last (past) year papers which are helpful to good score…

Absolutely yes, solving the last 3 to 8 years Q. papers are not only makes the students you stronger, but this also gives a confidence of questions which are coming in our JEE mains & Advanced exams. So try these papers as a BRAHMASTRA for your preparation of your JEE Advanced exams, because these given Question Papers will be helpful for getting full marks in JEE Advanced examination.

Past 10 year Q. Paper of 2006, 7, 8….. 16 and also available in the attached sheet for candidates and teachers. Last years Q. paper for Mains and Advanced Mathematics, Physics and Chemistry are a smart way to revise for main & advanced exams. Specially are helpful for those appearing for Advanced exam as they familiarize students with the patterns of the Solved Q.paper and the method of marking.

JEE Advanced Q. Papers are top revision tools and must be made an important part of exam preparation. Chemistry are issued by JEE Main/Advanced 2016-17. Chemistry Advanced syllabus 2015-16 was Chemical Bonding, Ionic Equilibrium, s-Block Elements, Solid State, p-Block elements, Surface Chemistry etc…… important question bank for JEE. How to score 90+ per-cent  on JEE Advanced examination practice the last 10 years question paper this Board for sure will prove to be the special tool in getting a high score end success in CBSE class XIIth Examinations,

Updated: October 17, 2018 — 5:49 pm
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