# JEE Advanced Physics Sample Paper on Kinematics in Two Dimensions with Answer & Solution 2019

**Subtopics of Kinematics in Two Dimensions**

### Displacement, Velocity, and Acceleration | Equations of Kinematics in Two Dimensions | Projectile Motion | Relative Velocity | Concepts & Calculations

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## Question Paper : Kinematics in Two Dimensions

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## Answer & Solution : Kinematics in Two Dimensions

Download JEE Advanced Physics Practice Sample Paper Answer and Solution. Our faculty team after a thorough analysis of the last years examination question papers and the latest examination jee advanced format, have framed these questions paper. Here you will find the questions picked from every important sub-topic of Jee Advanced Pattern. Each question has been provided with an appropriate though simple solution which is easy to understand thereby helping you make an easy and effective preparation.

**Kinematics in Two Dimensions**

*Displacement:* $\Delta \vec r = \vec r – {\vec r_0}$

*Average velocity:* ${\vec v_{ave}} = \frac{{\Delta \vec r}}{{\Delta t}} = \frac{{\vec r – {{\vec r}_0}}}{{t – {t_0}}}$

*Instantaneous velocity:* $\vec v = \mathop {\lim }\limits_{\Delta t \to 0} \frac{{\Delta \vec r}}{{\Delta t}}$

*Average acceleration:* ${\vec a_{ave}} = \frac{{\Delta \vec v}}{{\Delta t}} = \frac{{\vec v – {{\vec v}_0}}}{{t – {t_0}}}$

*Instantaneous acceleration:* $\vec a = \mathop {\lim }\limits_{\Delta t \to 0} \frac{{\Delta \vec v}}{{\Delta t}}$

**Note:** In two dimensional motion, each component (x and y) can be treated separately.

#### The x-component is independent of the y-component and vice versa. The two components are connected by time *t*.

*Equations of Constant Acceleration:*

*Equations of Constant Acceleration:*

#### ${\text{x – component of motion}}$ ${\text{y – component of motion}}$

#### ${v_x} = {v_{0x}} + {a_x}t$ ${v_y} = {v_{0y}} + {a_y}t$

#### $x – {x_0} = \frac{1}{2}({v_{0x}} + {v_x})t$ $y – {y_0} = \frac{1}{2}({v_{0y}} + {v_y})t$

#### $x – {x_0} = {v_{0x}}t + \frac{1}{2}{a_x}{t^2}$ $y – {y_0} = {v_{0y}}t + \frac{1}{2}{a_y}{t^2}$

#### $v_x^2 = v_{0x}^2 + 2{a_x}(x – {x_0})$ $v_y^2 = v_{0y}^2 + 2{a_y}(y – {y_0})$

*Projectile Motion:*

*Projectile Motion:*